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	<title>
	Comments on: T-SQL Tuesday &#8211; T-SQL Puzzle with HAVING	</title>
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	<link>https://lobsterpot.com.au/blog/2010/01/12/t-sql-tuesday-t-sql-puzzle-with-having/</link>
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		<title>
		By: robfarley		</title>
		<link>https://lobsterpot.com.au/blog/2010/01/12/t-sql-tuesday-t-sql-puzzle-with-having/#comment-720</link>

		<dc:creator><![CDATA[robfarley]]></dc:creator>
		<pubDate>Tue, 12 Jan 2010 15:54:47 +0000</pubDate>
		<guid isPermaLink="false">/blogs/robfarley/archive/2010/01/12/t-sql-tuesday-t-sql-puzzle-with-having.aspx#comment-720</guid>

					<description><![CDATA[Michael,

I think Kalen&#039;s is unexpected, but that mine just needs a good understanding of how HAVING works.

Make sure you read my explanation for it at http://msmvps.com/blogs/robfarley/archive/2010/01/12/t-sql-tuesday-having-puzzle-answer.aspx

Rob
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			<content:encoded><![CDATA[<p>Michael,</p>
<p>I think Kalen&#8217;s is unexpected, but that mine just needs a good understanding of how HAVING works.</p>
<p>Make sure you read my explanation for it at <a href="http://msmvps.com/blogs/robfarley/archive/2010/01/12/t-sql-tuesday-having-puzzle-answer.aspx" rel="nofollow ugc">http://msmvps.com/blogs/robfarley/archive/2010/01/12/t-sql-tuesday-having-puzzle-answer.aspx</a></p>
<p>Rob</p>
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		<item>
		<title>
		By: Michael J Swart		</title>
		<link>https://lobsterpot.com.au/blog/2010/01/12/t-sql-tuesday-t-sql-puzzle-with-having/#comment-719</link>

		<dc:creator><![CDATA[Michael J Swart]]></dc:creator>
		<pubDate>Tue, 12 Jan 2010 08:30:42 +0000</pubDate>
		<guid isPermaLink="false">/blogs/robfarley/archive/2010/01/12/t-sql-tuesday-t-sql-puzzle-with-having.aspx#comment-719</guid>

					<description><![CDATA[... that was unexpected. And strangely enough this is related to Kalen Delaney&#039;s T-SQL Tuesday entry here:

http://sqlblog.com/blogs/kalen_delaney/archive/2010/01/11/non-aggregated-columns-in-a-group-by-query.aspx]]></description>
			<content:encoded><![CDATA[<p>&#8230; that was unexpected. And strangely enough this is related to Kalen Delaney&#8217;s T-SQL Tuesday entry here:</p>
<p><a href="http://sqlblog.com/blogs/kalen_delaney/archive/2010/01/11/non-aggregated-columns-in-a-group-by-query.aspx" rel="nofollow ugc">http://sqlblog.com/blogs/kalen_delaney/archive/2010/01/11/non-aggregated-columns-in-a-group-by-query.aspx</a></p>
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		<item>
		<title>
		By: Michael		</title>
		<link>https://lobsterpot.com.au/blog/2010/01/12/t-sql-tuesday-t-sql-puzzle-with-having/#comment-718</link>

		<dc:creator><![CDATA[Michael]]></dc:creator>
		<pubDate>Mon, 11 Jan 2010 21:49:44 +0000</pubDate>
		<guid isPermaLink="false">/blogs/robfarley/archive/2010/01/12/t-sql-tuesday-t-sql-puzzle-with-having.aspx#comment-718</guid>

					<description><![CDATA[SELECT 1 + 1 will return 2, I have to assume that a column title &#039;no column name&#039; will contain a single value &#039;No rows&#039;... but I dont think it will return anything as the where condition is never going to be satisfied.]]></description>
			<content:encoded><![CDATA[<p>SELECT 1 + 1 will return 2, I have to assume that a column title &#8216;no column name&#8217; will contain a single value &#8216;No rows&#8217;&#8230; but I dont think it will return anything as the where condition is never going to be satisfied.</p>
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